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% operator in Bash serves three distinct syntactic roles depending on its evaluation context: an arithmetic modulo operator, a parameter expansion operator for suffix removal, and a job control specifier.
Arithmetic Modulo Operator
Within an arithmetic evaluation context,% functions as the modulo operator. It evaluates the remainder of integer division between two operands. Because Bash natively supports only integer arithmetic, floating-point operands will result in a syntax error.
Syntax:
- Evaluated exclusively inside Bash’s internal arithmetic contexts (
$(( )),(( )), orlet). - The sign of the result matches the sign of the dividend.
- Division by zero throws a
division by 0runtime error.
Parameter Expansion (Suffix Pattern Removal)
Within parameter expansion,% acts as a pattern-matching operator that strips a specified suffix from a variable’s string value. It uses standard shell globbing rules (not regular expressions) to match the pattern against the end of the string.
Syntax:
- Single
%(Non-greedy): Deletes the shortest possible match of thepatternfrom the right side (suffix) of the expanded$variable. - Double
%%(Greedy): Deletes the longest possible match of thepatternfrom the right side of the expanded$variable. - If the pattern does not match the suffix, the original string is returned unmodified.
Job Control Specifier
In an interactive shell environment (or scripts whereset -m is enabled), % is used as a prefix to reference background or suspended jobs by their job ID or command string, rather than their Process ID (PID).
Syntax:
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