TypeScript Strict Inequality

operand1 !== operand2

let str: string = "10";
let num: number = 10;

// Compiler Error ts(2367): This condition will always return 'true' 
// since the types 'string' and 'number' have no overlap.
const isDifferent = str !== num; 

let str: string = "10";
let num: number = 10;

// Bypassing the compiler check for non-overlapping types using 'unknown'
const isForcedDifferent = (str as unknown) !== num; 

let val1: string | number = "10";
let val2: number = 10;

// Valid compilation: 'val1' could potentially be a number, 
// so the types naturally overlap. Evaluates to true at runtime.
const isDifferent = val1 !== val2; 

const objA: { id: number } = { id: 1 };
const objB: { id: number } = { id: 1 };
const objC = objA;

const check1 = objA !== objB; // Valid compilation. Evaluates to true (different references).
const check2 = objA !== objC; // Valid compilation. Evaluates to false (same reference).